2x^2+2x-1225=0

Solution for 2x^2+2x-1225=0 equation:

2x^2+2x-1225=0

a = 2; b = 2; c = -1225;
Δ = b2-4ac
Δ = 22-4·2·(-1225)
Δ = 9804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9804}=\sqrt{4*2451}=\sqrt{4}*\sqrt{2451}=2\sqrt{2451}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{2451}}{2*2}=\frac{-2-2\sqrt{2451}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{2451}}{2*2}=\frac{-2+2\sqrt{2451}}{4}
$